24 lines
537 B
Python
24 lines
537 B
Python
'''
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【程序29】
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题目：给一个不多于5位的正整数，要求：一、求它是几位数，二、逆序打印出各位数字。
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1. 程序分析：学会分解出每一位数，如下解释：(这里是一种简单的算法，师专数002班赵鑫提供)
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2.程序源代码：
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'''
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x = int(raw_input("input a number:\n"))
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a = x / 10000
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b = x % 10000 / 1000
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c = x % 1000 / 100
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d = x % 100 / 10
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e = x % 10
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if a != 0:
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print "there are 5 ",e,d,c,b,a
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elif b != 0:
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print "there are 4 ",d,c,b,a
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elif c != 0:
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print "there are 3 ",e,d,c
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elif d != 0:
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print "there are 2 ",e,d
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else:
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print "there are 1",e
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